-17y^2=-68y

Solution for -17y^2=-68y equation:

-17y^2=-68y

We move all terms to the left:

-17y^2-(-68y)=0

We get rid of parentheses

-17y^2+68y=0

a = -17; b = 68; c = 0;
Δ = b2-4ac
Δ = 682-4·(-17)·0
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-68}{2*-17}=\frac{-136}{-34}
=+4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+68}{2*-17}=\frac{0}{-34}
=0
$